2012. 4. 17 1/3 semiconductor technical data KCR405T constant-current led driver transistor revision no : 2 led drive application. features h supplies stable bias current even at low battery voltage. h ideal for stabilizing bias current of leds. h negative temperature coefficient protects leds against thermal overload. 1. gnd2. output current 3. output current 4. source voltage 5. output current 6. rext dim millimeters a b d e ts6 2.9 0.2 1.6+0.2/-0.1 0.70 0.05 0.4 0.1 2.8+0.2/-0.3 1.9 0.2 0.95 0.16 0.05 0.00-0.10 0.25+0.25/-0.15 c f gh i j k0 . 6 0 l0 . 5 5 a f g g d k k b e c l h j j i 23 5 16 4 + _ + _ + _ + _ + _ equivalent circuitmaximum rating (ta=25 ? ) marking 654 123 characteristic symbol rating unit source voltage v s 40 v output current i o 65 ma output voltage v o 38 v reverse voltage between all terminals v r 0.5 v power dissipation p d * 900 mw junction temperature t j 150 ? storage temperature range t stg -55 q 150 ? type name ab 654123 lot no. *package mounted on a ceramic board (600 [ ? 0.8 x ) downloaded from: http:///
2012. 4. 17 2/3 KCR405T revision no : 2 electrical characteristics (ta=25 ? ) characteristic symbol test condition min. typ. max. unit collector-emitter breakdown voltage bv ceo i c =1ma, i b =0 40 - - v supply current i s v s =10v 340 420 500 u dc current gain h fe i c =50ma, v ce =1v 100 200 400 - internal resistor r int i rint =50ma 11 15 19 ? output current i o v s =10v 45 50 55 ma voltage drop (v s -v e ) v drop i o =50ma 0.7 0.75 0.8 v lowest sufficient battery voltage overhead v smin i o >18ma - 1.4 - v output current change versus ta i o /i o v s =10v - -0.15 - %/k output current change versus v s i o /i o v s =10v - 1 - %/v application circuit 1 2, 3, 5 ledled 6 4 +v s rext downloaded from: http:///
2012. 4. 17 3/3 KCR405T revision no : 2 source voltage v s (v) i o - v s output current i o (ma) 10 100 25 30 0 5 10 15 20 45 50 40 35 v s -v o =1.4v 56 ohm 82 ohm open source voltage v s (v) i o - v s output current i o (ma) source voltage v s (v) i o - v s output current i o (ma) 10 100 10 100 10 100 25 30 0 5 10 15 20 45 50 40 35 v s -v o =1.2v,2v v s -v o =1v source voltage v s (v) i s - v s supply current i s (ma) 0 0.2 0.4 0.6 0.8 1.0 1.2 1.4 1.6 1.8 2.0 25 30 051015 20 45 50 40 35 -40 c ta=25 c 25 30 051015 20 45 40 50 35 external resistor rext ( ) i o - r ext output current i o (ma) 10 100 20 c 80 c -40 c 20 c 80 c -40 c 20 c 80 c v s =10v v s -v o =1.4v v s -v o =1.4v downloaded from: http:///
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